1.

Solve the system of equations in R.x + 3 > 0, 2x < 14

Answer»

Given as x + 3 < 0 and 2x < 14

Now, let us consider the first inequality.

x + 3 < 0

x + 3 – 3 < 0 – 3

x < –3

Then, let us consider the second inequality.

2x < 14

Dividing both the sides by 2 we get,

2x/2 < 14/2

x < 7

Therefore, the solution of the given system of inequation is (–3, 7).



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