Solve the system of equations: x – 2y = 0, 3x + 4y = 20.

1.	Solve the system of equations: x – 2y = 0, 3x + 4y = 20.
Answer» The given equations are as follows: x – 2y = 0 ………….(i) 3x + 4y = 20 …………(ii) On multiplying (i) by 2, we get: 2x – 4y = 0 …………(iii) On adding (ii) and (iii), we get: 5x = 20 ⇒ x = 4 On substituting x = 4 in (i), we get: 4 – 2y = 0 ⇒ 4 = 2y ⇒ y = 2 Hence, the required solution is x = 4 and y = 2.

Answer»

The given equations are as follows:

x – 2y = 0 ………….(i)

3x + 4y = 20 …………(ii)

On multiplying (i) by 2, we get:

2x – 4y = 0 …………(iii)

On adding (ii) and (iii), we get:

5x = 20 ⇒ x = 4

On substituting x = 4 in (i), we get:

4 – 2y = 0 ⇒ 4 = 2y ⇒ y = 2

Hence, the required solution is x = 4 and y = 2.

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