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Solve with due regard to significant figures. 46.7-10.4(3.0xx10^(-8))+(4.5xx10^(-6))= |
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Answer» Solution :`46.7-10.04` Here `46.7`has one decimal PLACE , and `10.04`has TWO decimal places. `:. 46.7-10.04=36.66`. The RESULT should have only one decimal place . The result is `36.7`. `3.0xx10^(-8)+4.5xx10^(-6)=0.03xx10^(-6)=0.003xx10^(-6)+4.5xx10^(-6)=4.53xx10^(-6)` here `4.5xx10^(-6)`has only one decimal place and `0.03xx10(-6)`can have two decimal places. this result should be rounded off to one decimal place . `:.(3.0xx10^(-8))+(4.5xx10^(-6))=4.5xx10^(-6)` |
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