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Solve with due regard to significant figures. 46.7-10.4(3.0xx10^(-8))+(4.5xx10^(-6))=

Answer» <html><body><p></p>Solution :`46.7-10.04`<br/> Here `46.7`has one decimal <a href="https://interviewquestions.tuteehub.com/tag/place-1155224" style="font-weight:bold;" target="_blank" title="Click to know more about PLACE">PLACE</a> , and `10.04`has <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> decimal places. <br/>`:. 46.7-10.04=36.66`.<br/> The <a href="https://interviewquestions.tuteehub.com/tag/result-1187343" style="font-weight:bold;" target="_blank" title="Click to know more about RESULT">RESULT</a> should have only one decimal place . The result is `36.7`.<br/>`3.0xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>)+4.5xx10^(-6)=0.03xx10^(-6)=0.003xx10^(-6)+4.5xx10^(-6)=4.53xx10^(-6)`<br/>here `4.5xx10^(-6)`has only one decimal place and `0.03xx10(-6)`can have two decimal places. <br/> this result should be rounded off to one decimal place .<br/>`:.(3.0xx10^(-8))+(4.5xx10^(-6))=4.5xx10^(-6)`</body></html>


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