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Solve `|x^2-x-2|+|x+6|=|x^2-2x-8|` |
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Answer» Correct Answer - `x in (- oo ,-6 ] cup [-1,2]` `|x^2-x-2|+|x+6|=|x^2-2x-8|` or `|x^2-x-2|+|x+6|=(x^2-x-2)-(x+6)|` or `|x^2-x-2|+|-x-6|=|(x^2-x-2)+(-x-6)|` or `(x^2-x-2)(-x-6)ge 0 ` or `(x^2-x-2)(x+6) le 0 ` or `(x-2)(x+1)(x+6) le 0 ` or ` x in (-oo,-6] cup [-1,2]` |
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