Solve: x – 2y = 0, 3x + 4y = 20.

1.	Solve: x – 2y = 0, 3x + 4y = 20.
Answer» x – 2y = 0 ⇒ x = 2y. … (1) 3x + 4y = 20. … (2) Now putting x = 2y from equation (1) into equation (2), we get 3 (2y) + 4Y = 20 ⇒ 6y + 4Y = 20 ⇒ 10y = 20 ⇒ y = \(\frac{20}{10}\) = 2. Now, putting y = 2 in equation (1), we get x = 2y = 2× 2 = 4. Hence, the solution of given system of equations is x = 4 & y = 2.

Answer»

x – 2y = 0 ⇒ x = 2y. … (1)

3x + 4y = 20. … (2)

Now putting x = 2y from equation (1) into equation (2), we get

3 (2y) + 4Y = 20

⇒ 6y + 4Y = 20

⇒ 10y = 20

⇒ y = \(\frac{20}{10}\) = 2.

Now, putting y = 2 in equation (1), we get x = 2y = 2× 2 = 4.

Hence, the solution of given system of equations is x = 4 & y = 2.

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Solve: x – 2y = 0, 3x + 4y = 20.

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