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Solve : (x + log y)dy + ydx = 0 |
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Answer» Given differential equation can be written as (xdy + ydx) + log y. dy = 0 or, d(xy) + log y dy = 0 Integrating we get ∫d(xy) + ∫log y dy = c xy + y log y - y = c which is the required solution. |
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