1.

Solve : (x + log y)dy + ydx = 0

Answer»

Given differential equation can be written as

(xdy + ydx) + log y. dy = 0

or, d(xy) + log y dy = 0 

Integrating we get

∫d(xy) + ∫log y dy = c

xy + y log y - y = c

which is the required solution.



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