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Some amount of ..20V..H_(2)O_(2) is mixed with excess of acidifeid solution KI. The iodine so liberated required 200ml of 0.IN Na_(2)S_(2)O_3for tritration. The volume of H_2O_2 solution is |
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Answer» 11.2 ml `V_1N_1 =V_2N_2` `V_(1) XX(20)/(5.6) = 200 xx0.1` VOL. of `H_2O_2` solution = 5.6 ml |
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