1.

Some iron beads are embedded in wax ball which is just floating in water. The volume of ball is 18 cm^(3) and relative density of waxis 0.9 .Then mass of the iron trapped in the ball is

Answer»

1.8 g
2.7 g
16.8 g
8.1 g

Solution :LET the mass of iron trapped in the ball be m.
According to law of floatation ,
Weight = upthrust
(m + mass of wax)g `=18 xx 1xx g`
IGNORING the volume of iron SINCE it is in the FORM of small BEADS
`therefore m+18 xx0.9-18xx1` or `m=1.8 g`


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