Some liquid is filled in a cylindrical vessel of radius R. Let `F_(1)` be the force applied by the liquid on the bottom of the cylinder. Now the same liquid is poured into a vessel of uniform square cross-section of side R. Let `F_(2)` be the force applied by the liquid on the bottom of this new vessel. (Neglect atmosphere pressure). ThenA. `F_(1)=piF_(2)`B. `F_(1)=F_(2)/pi`C. `F_(1)=sqrt(pi)F_(2)`D. `F_(1)=F_(2)`

Some liquid is filled in a cylindrical vessel of radius R. Let `F_(1)`

1.	Some liquid is filled in a cylindrical vessel of radius R. Let `F_(1)` be the force applied by the liquid on the bottom of the cylinder. Now the same liquid is poured into a vessel of uniform square cross-section of side R. Let `F_(2)` be the force applied by the liquid on the bottom of this new vessel. (Neglect atmosphere pressure). ThenA. `F_(1)=piF_(2)`B. `F_(1)=F_(2)/pi`C. `F_(1)=sqrt(pi)F_(2)`D. `F_(1)=F_(2)`
Answer» Correct Answer - D Force on base = mg of liquid implies `F_(1)=F_(2)`

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