InterviewSolution
Saved Bookmarks
| 1. |
Some measures are given in the figure, find the area of ☐ABCD. |
|
Answer» A(☐ABCD) = A(∆BAD) + A(∆BDC) In ∆BAD, m∠BAD = 90°, l(AB) = 40m, l(AD) = 9m A(∆BAD) = x product of sides forming the right angle = \(\cfrac{1}{2}\)x l(AB) x l(AD) =\(\cfrac{1}{2}\) x 40 x 9 = 180 sq. m In ∆BDC, l(BT) = 13m, l(CD) = 60m A(∆BDC) = \(\cfrac{1}{2}\)x base x height = \(\cfrac{1}{2}\)x l(CD) x l(BT) = \(\cfrac{1}{2}\)x 60 x 13 = 390 sq. m A (☐ABCD) = A(∆BAD) + A(∆BDC) = 180 + 390 = 570 sq. m ∴ The area of ☐ABCD is 570 sq.m. |
|