Some times a reacant undergoes chemical/radioactive changes followingtwo or more different pathsto yield twoor more different producesrespectively. Such reactions are called parallel path reactions. If K_(1) and K_(2) are rate constans for the reaction of A follwing two parallel paths, then Then K_(av) = K_(1) + K_(2) For if E_(1) and E_(2) are energy fo activations, then

Some times a reacant undergoes chemical/radioactive changes followingt

1.	Some times a reacant undergoes chemical/radioactive changes followingtwo or more different pathsto yield twoor more different producesrespectively. Such reactions are called parallel path reactions. If K_(1) and K_(2) are rate constans for the reaction of A follwing two parallel paths, then Then K_(av) = K_(1) + K_(2) For if E_(1) and E_(2) are energy fo activations, then
Answer» `E_("Total") = E_(1) + E_(2)` `E_("Total") = E_(1) - E_(2)` `E_("Total") = K_(1) E_(1) + K_(2)E_(2)` `E_("Total") = (K_(1) E_(1) + K_(2)E_(2))/(K_(1) + K_(2))` Solution :`K_(av) = K_(1) + K_(2)` `A_(T)E^(-E_(T)//RT^(2)) = A_(1) e^(-E_(1)//RT^(2)) + A_(2) e^(-E_(2)//RT^(2))` ....(1) DIFFERENTIATING EQN. (1) `A_(T). (E_(T))/(RT).e^(-E_(T)//RT^(2)) = A_(1). (E_(1))/(RT).e^(-E_(1)//RT^(2)) + A_(2) (E_(2))/(RT) e^(-E_(2)//RT^(2))` `K_(av) (E_(T))/(RT) = (K_(1)E_(1))/(RT) + (K_(2) E_(2))/(RT)` `(K_(1) + K_(2)) (E_(T))/(RT) = (K_(1)E_(1))/(RT) + (K_(2) E_(2))/(RT)` `:. E_(T) = (K_(1) E_(1) + K_(2) E_(2))/(K_(1) + K_(2))`