1.

Sound of freqeuncy 1000 Hz from a stationary source is reflectd form an object approaching the source is 30 ms^(-1), back to a stationary observer located at the source. The speed of sound in a air is 330 ms^(-1). The frequency of the sound heard by the observer is :

Answer»

1000 Hz
1100 Hz
1200 Hz
1090 Hz

Solution :The frequency of sound from the stationary source reaches the OBJECT which is approaching towards the source is
`v'=v_(0)((v+v_(0))/(v))`
When `v_(0)`= frequency of source
v= SPEED of sound in AIR
`v_(0)`= speed of the object
The frequency of reflected sound from the object heard by the stationary observer located at the source is
`v''=v''((v)/(v-v_(0)))=v_(0)((v+v_(0))/(v-v_(0)))`
`=1000 ((330+30)/(330-30))=1200 Hz`


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