1.

Species having same bond order are :

Answer»

`N_(2)`
`N_(2)^(-)`
`F_(2)^(+)`
`O_(2)^(-)`

Solution :(C, D)
Bond order of the following SPECIES are calculated using MOLECULAR orbital electronic CONFIGURATION and OBTAIN as`N_(2) = 3 , N_(2)^(-) = 2.5 , F_(2)^(+) = 1.5 , O_(2)^(-)`= 1.5


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