Specific conductivity of a 0.12 normal solution of an electrolyte is 0.023 `ohm^(-1)cm^(-1)`. Determine its equivalent conductivity.

Specific conductivity of a 0.12 normal solution of an electrolyte is 0

1.	Specific conductivity of a 0.12 normal solution of an electrolyte is 0.023 `ohm^(-1)cm^(-1)`. Determine its equivalent conductivity.
Answer» Correct Answer - 200 `ohm^(-1)cm^(2)eq^(-1)` `wedge_(eq)=kappaxx(1000)/("Normality")=0.024Omega^(-1)cm^(-1)xx(1000cm^(3)L^(-1))/(0.12g" "eqL^(-1))=200Omega^(-1)cm^(2)eq^(-1)`.

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Specific conductivity of a 0.12 normal solution of an electrolyte is 0.023 `ohm^(-1)cm^(-1)`. Determine its equivalent conductivity.

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