InterviewSolution
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InterviewSolution
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Specific heat of a monoatomic gas at constant volume is `315 J kg^(-1) K^(-1)` and at a contant pressure is `525 J kg^(-1) K^(-1)`. Calculate the molar of the gas. |
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Answer» `C_(P) = M xx 525 " and " C_(V) = M xx 315` where, M is the molecular mass. `C_(P) - C_(V) = R (R = 8.314 J K^(-1) mol^(-1))` `M xx 525 - M xx 315 = 8.314` `M (525 - 315) = 8.314` `M = (8.314)/(210) = 0.0396 kg mol^(-1) = 39.6 g mol^(-1)` |
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