1.

Specific heat ofan elementary gas is found to be 0.313 J at constant volume. If the molar mass of the gasis 40 g mol^(-1) , what is the atomicity of the gas ?

Answer»


Solution :`C_(v) = 0.313 xx 40 = 12.52J MOL^(-1) , C_(p) = C_(v)+R = 12.52 + 8.31= 20.83Jmol^(-1)`
`:. C_(p) //C_(v) = 20.83 // 12.52 = 1.66`


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