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Specific volume of cylindrical virus particle is 6.02×10−2ccg, whose radius and length arc 7∘A respectively. If NA=6.02×1023, find molecular weight of virus. |
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Answer» Specific volume of cylindrical virus particle is 6.02×10−2ccg, whose radius and length arc 7∘A respectively. If NA=6.02×1023, find molecular weight of virus. |
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