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Specific volume of cylindrical virus particle is 6.02*10^-2 cc/gm whose radius and length are 7A° and 10A° respectively.If NA =6.02*10^23,find molecular weight of virus.

Answer» Specific volume of cylindrical virus particle is 6.02*10^-2 cc/gm whose radius and length are 7A° and 10A° respectively.If NA =6.02*10^23,find molecular weight of virus.


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