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Specific volume of cylindrical virus particle is 6.02*10^(-2) cc/gm whose radius and length are 7 angstrom and 10 angstrom respectively. If NA= 6.02*10^23 find the molecular weight of virus. |
| Answer» Specific volume of cylindrical virus particle is 6.02*10^(-2) cc/gm whose radius and length are 7 angstrom and 10 angstrom respectively. If NA= 6.02*10^23 find the molecular weight of virus. | |