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Speed of a particle moving on a circular path of radius 2m is varying with time as v=(2t^)m/s. Net acceleration of the particle at t=2s is 8√n m/s^2. The value of n is

Answer» Speed of a particle moving on a circular path of radius 2m is varying with time as v=(2t^)m/s. Net acceleration of the particle at t=2s is 8√n m/s^2. The value of n is


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