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Speed of sound wave is v. If a reflector moves towards a stationary source emitting waves of frequency f with speed u, the wavelength of reflected waves will beA. `(v-u)/(v+u)f`B. `(v+u)/(v)f`C. `(v+u)/(v-u)f`D. `(v-u)/(v)f` |
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Answer» Correct Answer - C Apparent frequency for reflector (which will act here as an observer) would be `f_1=((v+u)/(v))f` Where f is the actual frequency of source. The reflector will now behave as a source. The apparent frequency will now become `f_2=((v)/(v-u))f_1` Substituting the value of `f_1` we get `f_2=((v+u)/(v-u))f` |
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