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Speeds of two identical cars are u and 4u at a specific instant. The ratio of the respective distances in which two cars are stopped from that instant. |
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Answer» `1:1` `THEREFORE = ((0)^(2) - u ^(2))/( 2A)` `therefore d =- ( u^(2))/( 2a),` here `-(1)/(2a) ` is CONSTANT. `therefore d alpha u ^(2)` `therefore (d _(1))/(d _(2)) = ((u _(1))/( u _(2)))^(2) = ((u)/( 4u )) ^(2)` `therefore (d _(1))/(d_(2)) = (1)/(16)` `therefore d _(1) : d _(2) =1 :16` |
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