Sphere of mass M and radius R is surrounded by a spherical shell of mass 2M and radius 2R as shown. A small particle of mass m is released from rest from a height h(ltltR) above the shell. There is hole in the shell. What time will it take to move from A to B?

Sphere of mass M and radius R is surrounded by a spherical shell of

1.	Sphere of mass M and radius R is surrounded by a spherical shell of mass 2M and radius 2R as shown. A small particle of mass m is released from rest from a height h(ltltR) above the shell. There is hole in the shell. What time will it take to move from A to B?
Answer» `=(R^(2))/(sqrt(GMh))` `gt(R^(2))/(sqrt(GMh))` `lt(R^(2))/(sqrt(GMh))` none of these Solution : `r_(1)=a-ae=a(1-e)` `r_(2)=a+ae=a(1+e)....(i)` `mV_(1)r_(1)sin90^(@)=mV_(2)r_(2) sin 90^(@)` `V_(1)r_(1)=V_(2)r_(2)......(ii)` According to conservation of ENERGY at `P` and `A` `1/2mV_(1)^(2)-(GMm)/(r_(1))=1/2mV_(2)^(2)-(GMm)/(r_(2))....(iii)` From `(i),(ii)` and `(iii) V_(1)=sqrt((GM)/a((1+e)/(1-e)))`