\(\sqrt{(0.798)^2+0.404\times 0.798+(0.202)^2}\) is equal to(a) 0 (b – InterviewSolution

1.

\(\sqrt{(0.798)^2+0.404\times 0.798+(0.202)^2}\) is equal to(a) 0 (b) 2 (c) 1.596 (d) 0.404

Answer»

(b) 2

Given exp.

= \(\sqrt{(0.798)^2+2\times0.202\times0.798+(0.202)^2}\) +1

= \(\sqrt{(0.798+0.202)^2}+1\)

= \(\sqrt1\) + 1 = 1 + 1 = 2

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