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`sqrt(ax+b)` |
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Answer» `int sqrt(ax+b)dx" माना "ax+b=t` `=intsqrtt (dt)/(a)=(1)/(a).intt^(1//2)dt" "rArr dx=dt` `=(1)/(a).(t^(3//2))/(3//2)+c" "rArr dx=(dt)/(a)` `=(2)/(3a)(ax+b)^(3//2)+c` |
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