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` sqrt(sin 2x) cos 2x`A. `(1)/(3)(sinx)^(3//2)+C`B. `(1)/(3)(sin x)^(1//2)+C`C. `(1)/(3)(sin 2x)^(3//2)+C`D. `(1)/(3)(sin 2x)^(1//2)+C` |
Answer» Correct Answer - C `intsqrt(sin2x)cos 2xdx` Let `" "sin2x=t" "rArr" "2cos 2x=(dt)/(dx)` `rArr" "dx=(dt)/(2cos 2x)` `therefore int sqrt(sin2x)cos 2x dx=intsqrtt cos 2x(dt)/(2cos 2x)=(1)/(2)int sqrtt dt` `=(1)/(2)(t^(1//2+1))/(((1)/(2)+1))+C=(1)/(3)t^(3//2)+C` `=(1)/(3)(sin2x)^(3//2)+C` |
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