सर N) (1+tan 0 +sec0) (1 + cot © — cosec 9) बराबर ह

1.	सर N) (1+tan 0 +sec0) (1 + cot © — cosec 9) बराबर है
Answer» (1+cot A -cosec A)(1+ tan A + sec A) Lhs =(1 +cos A/sin A - 1/sin A)(1 + sin A/cos A +1/cos A) =(sin A+cos A -1/sin A)(cos A +sin A+1/cos A) =(sin A+cos A-1)(sin A+cos A+1)/sin Acos A =[(sin A+cos A)^2-(1)^2]/sin Acos A =[sin^2A+cos^2A +2sin Acos A- 1]/sin Acos A =[1-1+2sin Acos A]/sin Acos A =2sin Acos A/sin Acos A =2 =Rhs

सर N) (1+tan 0 +sec0) (1 + cot © — cosec 9) बराबर है

Answer»

(1+cot A -cosec A)(1+ tan A + sec A)

Lhs

=(1 +cos A/sin A - 1/sin A)(1 + sin A/cos A +1/cos A)

=(sin A+cos A -1/sin A)(cos A +sin A+1/cos A)

=(sin A+cos A-1)(sin A+cos A+1)/sin Acos A

=[(sin A+cos A)^2-(1)^2]/sin Acos A

=[sin^2A+cos^2A +2sin Acos A- 1]/sin Acos A

=[1-1+2sin Acos A]/sin Acos A

=2sin Acos A/sin Acos A

=2 =Rhs