ss lia'a cakes İ İkur lets 'han a passenger train to travel iMysore and Bangalore (without taking into consideration the timente mediate stations, İl ihe average speed of the express train is l i km/hof the passenges tuin, find the average speed of the two tainsSum of the arcas of two 4tind the sides of the two squares.the time theyIkm/b more thao squates is 468 m'If the difference of their perimeters is

ss lia'a cakes İ İkur lets 'han a passenger train to travel iMysore

1.	ss lia'a cakes İ İkur lets 'han a passenger train to travel iMysore and Bangalore (without taking into consideration the timente mediate stations, İl ihe average speed of the express train is l i km/hof the passenges tuin, find the average speed of the two tainsSum of the arcas of two 4tind the sides of the two squares.the time theyIkm/b more thao squates is 468 m'If the difference of their perimeters is
Answer» 10)Solution:-Let the average speed of the passenger train be 'x' km/hr and the average speed of the express train be (x + 11) km/hrDistance between Mysore and Bangalore = 132 kmIt is given that the time taken by the express train to cover the distance of 132 km is 1 hour less than the passenger train to cover the same distance.So, time taken by passenger train = 132/x hrThe time taken by the express train = {(132)/x+11} hrNow, according to the question{132/(x+11)} = 132/x + 1After taking L.C.M. of 132/x +1 and then solving it we get (132+x)/x.Now,{132/(x+11)} = (132+x)/xBy cross multiplying, we get132x = x²+132x+11x+1452x² +11x - 1452 = 0x² + 44x - 33x - 1452 = 0x(x+44) - 33(x+44) = 0(x+33) (x+44) = 0x - 44 or x = 33As the speed cannot be in negative therefore, x = 33 or the speed of the passenger train = 33 km/hr and the speed is 33 + 11 = 44 km/hrAnswer.