Standard electrode potential values Fe^(2+)//Fe,E^(@)=-0.44 V , Fe^(3+)//Fe^(2),E^(@)=0.77 v If Fe^(2+),Fe^(3+) and Fe blocks are kept together it will lead to

Standard electrode potential values Fe^(2+)//Fe,E^(@)=-0.44 V , Fe^(3

1.	Standard electrode potential values Fe^(2+)//Fe,E^(@)=-0.44 V , Fe^(3+)//Fe^(2),E^(@)=0.77 v If Fe^(2+),Fe^(3+) and Fe blocks are kept together it will lead to
Answer» increase in `Fe^(3+)` DECREASE in `Fe^(3+)` `Fe^(2+)//Fe^(3+)` REMAINS unchanged `Fe^(2+)` decreases Solution :Higher is the `E^(@)` stronger is the OXIDISING agent THUS `Fe^(3+)` with `E^(@)=0.77V` is the stronger oxidising agent `Fe^(3+)+e^(-)rarrFe^(2+)` Thus the amount of `Fe^(3+)` will decrease