1.

Standard enthalpy of vaporisation Delta_("vap") H^(@) for water at100^(@)C is40.66 kJ mol^(-1) . The internal energy change of vaporisation of water at100^(@)C ( in kJmol^(-1)) is:

Answer»

`+37.56`
`-43.76`
`+ 43.76`
`+40.66`

Solution :`underset(1 "mole")(H_(2)O(l)) rarrunderset("1 mole")(H_(2)O(g)), Deltan_(g)=1`
`DeltaU =DeltaH - Deltan_(g)RT`
`= 40.66xx 1000 J mol^(-1)-1 XX 8.314 JK^(-1) xx 373 K`
`= 40660 - 3101 J mol^(-1)`
`=37559 J mol^(-1)`
`=37. 56 kJ mol^(-1)`


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