Standard entropies of X_(2), Y_(2) andXY_(3) are 60,40 and 50JK^(-1)mol^(-1) respectively. For the reaction(1)/(2)X_(2) + (3)/(2)Y_(2) hArr XY_(3) , DeltaH= - 30 kJto be at equilibrium, the temperature should be

Standard entropies of X_(2), Y_(2) andXY_(3) are 60,40 and 50JK^(-1)mo

1.	Standard entropies of X_(2), Y_(2) andXY_(3) are 60,40 and 50JK^(-1)mol^(-1) respectively. For the reaction(1)/(2)X_(2) + (3)/(2)Y_(2) hArr XY_(3) , DeltaH= - 30 kJto be at equilibrium, the temperature should be
Answer» 500K 750 K 1000K 1250 K Solution :`(1)/(2) X_(2) + ( 3)/(2)Y_(2) HARR XY_(3)` `DeltaS^(@) = SigmaS_(P)^(@) - Sigma _(R)^(@) = 50-( 30+60) = - 40 JK^(-1) MOL^(-1)` `DeltaG^(@) =DeltaH^(@) - T DeltaS^(@) ` . At equilibrium , `DeltaG^(@) = 0`. HENCE,`TDELTAS^(@) = DeltaH^(@)` or `T= (DeltaH^(@))/( DeltaS^(@)) = ( -30 xx 10^(3) J mol^(-1))/( -40JK^(-1) mol^(-1))= 750 K`