Standard vaporisation enthalpy of benzene at its boiling point is 230.8 kJ mol^(-1) . For how long would a 100 W electricheater have to operate to vaporize a 100 g sample of benezene at its boiling temperature? ( power = energy // time , 1 W = 1 J s^(-1))

Standard vaporisation enthalpy of benzene at its boiling point is 230.

1.	Standard vaporisation enthalpy of benzene at its boiling point is 230.8 kJ mol^(-1) . For how long would a 100 W electricheater have to operate to vaporize a 100 g sample of benezene at its boiling temperature? ( power = energy // time , 1 W = 1 J s^(-1))
Answer» Solution :1 moleof benezene , `C_(6) H_(6) (78 G)` requires energy for VAPORIZATION `= 30.8kJ` `:. 100g` benezenewill require energy `= (30.8) /( 78) xx 100 J = 39.5 kJ` 100 Wheater gives energy of 100 J per second `:. ` Time required for GETTING 39.5 kJ of energy`= (39500 J )/(100J ) = 395 sec = 6` min 35 sec.