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Starting at rest , `a 10kg` object is acted upon by only one force as indicated in figure. Then the total work done by the force is `:` A. `90J`B. `125J`C. `245J`D. `490J` |
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Answer» Correct Answer - B Change in velocity `= ( area underF-T graph)/(mass )` `=(60+(-10))/(10)=5m//s` `W_(F)=DeltaK.E. =(1)/(2)(10)5^(2)=125J` |
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