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Starting from methyl magnesium iodide how would you prepare (i) Ethanol (i) 2-propanol(iii) Tert-butyl alcohol. |
Answer» Solution :(i) Ethanol: Formaldehyde REACTS with `CH_3MgI` to GIVE an ADDITION PRODUCT which on hydrolysis yields ethanol.  (ii) 2-Propanol: ACETALDEHYDE react with `CH_3MgI`to give an addition product which on hydrolysis yields 2-propanol. 
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