1.

Starting from methyl magnesium iodide, how would you prepare (i) Ethyl methyl ether (ii) methyl cyanide (iii) methane.

Answer»

Solution :(i) ETHYL methyl ether: Lower haBogenated ether reacts with grignard reagent to form HIGHER ether.
`underset("Chloro dim ethyl ether")(CH_3 - O - CH_2Cl) + underset("iodide")underset("Methyl magnesium")(CH_3MgI) to underset("ETHYLMETHYL ether")(CH_3 - O - CH_2 - CH_3)`
(II) Methyl cyanide: Grignard reagent reacts with cyanogen chloride to form alkyl cyanide.

(iii) Methane: Grignard reagent reacts with water to give methane as product.


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