InterviewSolution
Saved Bookmarks
| 1. |
Starting with a sample of pure `.^66 Cu, 7//8` of it decays into `Zn` in `15 min`. The corresponding half-life is.A. 5 minB. `7(1)/(2)min`C. 10 minD. 15 min |
|
Answer» Correct Answer - A According to the question, (7/8) part decays i.e., remaining part is (1/8). We have, `N =N_(0)((1)/(2))^((t)/(T_(1//2)))implies1/8((1)/(2))^((15)/(T_(1//2)))` `implies"Half-life"T_(1//2)=5min` |
|