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Starting with a sample of pure `.^66 Cu, 7//8` of it decays into `Zn` in `15 min`. The corresponding half-life is.A. 5 minB. `7(1)/(2)min`C. 10 minD. 15 min

Answer» Correct Answer - A
According to the question, (7/8) part decays i.e., remaining part is (1/8).
We have, `N =N_(0)((1)/(2))^((t)/(T_(1//2)))implies1/8((1)/(2))^((15)/(T_(1//2)))`
`implies"Half-life"T_(1//2)=5min`


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