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State and Prove Idempotent law algebraically?? |
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Answer» Idempotent Law – An input that is AND´ed or OR´ed with itself is equal to that input A + A = A A variable OR’ed with itself is always equal to the variable A . A = A A variable AND’ed with itself is always equal to the variable Proof: x + x = (x + x) • 1 (1 is the identity for AND) = (x + x) • (x + x') (Complement, x + x' = 1) = x + (x • x') (OR distributes over AND) = x + 0 (Complement, x • x' = 0) = x (0 is the identity for OR) |
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