State and prove work energy theorem in case of rectilinear motion unde

1.	State and prove work energy theorem in case of rectilinear motion under constant acceleration.
Answer» work energy theorem state that change in kinetic energy of an object is equal to the net work done on it by the net force W = K_f- k_i where k_f = final kinetic energy k_i= initial kinetic energy for rectilinear motion and constant acceleration. v² - u² = 2as......(1) where v = final speed, u = initial speed. multiplying equation (1) both side by \(\cfrac{m}2\) \(\cfrac{1}2\)mv² - \(\cfrac{1}2\)mu² = \(\cfrac{m}2\) .2 as \(\because\) F = ma \(\cfrac{1}2\)mv² - \(\cfrac{1}2\)mu² = F.s \(\because\) W = F.s then \(\cfrac{1}2\)mv² - \(\cfrac{1}2\)mu² = W K_f- k_i = W work is done by a force on the body over a certain displacement. The change in kinetic energy of a particle is equal to the work done on it by the net force.

State and prove work energy theorem in case of rectilinear motion under constant acceleration.

Answer»

work energy theorem state that change in kinetic energy of an object is equal to the net work done on it by the net force

W = K_f- k_i

where k_f = final kinetic energy

k_i= initial kinetic energy

for rectilinear motion and constant acceleration.

v² - u² = 2as......(1)

where v = final speed, u = initial speed.

multiplying equation (1) both side by \(\cfrac{m}2\)

\(\cfrac{1}2\)mv² - \(\cfrac{1}2\)mu² = \(\cfrac{m}2\) .2 as

\(\because\) F = ma

\(\cfrac{1}2\)mv² - \(\cfrac{1}2\)mu² = F.s

\(\because\) W = F.s then

\(\cfrac{1}2\)mv² - \(\cfrac{1}2\)mu² = W

K_f- k_i = W

work is done by a force on the body over a certain displacement. The change in kinetic energy of a particle is equal to the work done on it by the net force.

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