1.

& State ‘bau.—c हर हा ही हा ््ज gow aus'ux’t I

Answer»

False.

Reason :

We know √2 is irrational.

Let assume √2/3 be rational

So, √2/3 = r, where is some rational number

So, √2 = 3r,

Therefore this is a contradiction as LHS is irrational and RHS is rational, a contradiction to our assumption that √2/3 is rational so it is irrational.

Hit like and BeScholr

false, because root 2 is not a rational number.......



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