State Faraday’s first law of electrolysis. For the electrode reactio

1.	State Faraday’s first law of electrolysis. For the electrode reaction Zn2+ + 2e– → Zn(s), What quantity of electricity in coulombs required to deposit one mole of zinc.
Answer» Faraday’s law states that “The amount of chemical reaction which occurs at any electrode during electrolysis by a current is directly proportional to the quanting of electricity passed through the electrolyte. To deposit one mole of zinc 2 × 96500 = 1,93,000 C of electricity is required.

State Faraday’s first law of electrolysis. For the electrode reaction Zn2+ + 2e– → Zn(s), What quantity of electricity in coulombs required to deposit one mole of zinc.

Answer»

Faraday’s law states that “The amount of chemical reaction which occurs at any electrode during electrolysis by a current is directly proportional to the quanting of electricity passed through the electrolyte.

To deposit one mole of zinc

2 × 96500 = 1,93,000 C of electricity is required.

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State Faraday’s first law of electrolysis. For the electrode reaction Zn2+ + 2e– → Zn(s), What quantity of electricity in coulombs required to deposit one mole of zinc.

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