State Henry's law for slubility of a gas in a liquid. Explain the significance of Henry's law constnat (K_(H)). At the same temperatue, hydrogen is more soluble in water than helium. Which of them will have a higer value of K_(H)and Why?

State Henry's law for slubility of a gas in a liquid. Explain the sign

1.	State Henry's law for slubility of a gas in a liquid. Explain the significance of Henry's law constnat (K_(H)). At the same temperatue, hydrogen is more soluble in water than helium. Which of them will have a higer value of K_(H)and Why?
Answer» Solution :Henry.s law states that the solubility of a gas in liquid at a given temperature is directly PROPORTIONAL to the partial pressure of the gas. `P _(k _(H)X` where P is the pressure of the gas, x is the mole fraction of the gas in the solution and `K_(H)` is the Henry.s law constant. `K_(H)` is a function of the nature of gas. Higher the value of `K_(H)` at a given temperature, lower is the solubility of the gas in the liquid. As helium is less soluble in water, so it has a higher value of `K_(H)` than hydrogen. Henry.s Law: As dissolution of AGAR in liquid is an exothermic PROCESS, therefore, the solubility should decrease with in increase in temperature.