State in each case whehterA sub B or A cancel(sub)B. (i) A={0,1,2,3} ,B={1,2,3,4,5} (ii) A=phi, B ={0} (iii) A= {1,2,3} , B= {1,2,4} (iv) A ={x:x in Z, x^2=1}, B={x:x in N X^2=1} (v)A= {x:x " is a even natural number "},B={x:x " is a integer " } (vii) A={x:x " is a real number "}, B= {x:x " is a complex number"} (viii) A={x :x " is an isosceles triangle in a planel, B={x:x" is an equilateral triangle in the same plane "} (ix) A={x:x " is a square in a plane "} B={x:x " is a rectangle in the same plane "} (x) A={x:x" is a triangle in a plane "}, B=(x:x " is a rectangle in the same plane"}, (xi) A={x:x " is an even natural number less than " 8} B={x:x " is a natural number which divides" 32}.

State in each case whehterA sub B or A cancel(sub)B. (i) A={0,1,2,3}

1.	State in each case whehterA sub B or A cancel(sub)B. (i) A={0,1,2,3} ,B={1,2,3,4,5} (ii) A=phi, B ={0} (iii) A= {1,2,3} , B= {1,2,4} (iv) A ={x:x in Z, x^2=1}, B={x:x in N X^2=1} (v)A= {x:x " is a even natural number "},B={x:x " is a integer " } (vii) A={x:x " is a real number "}, B= {x:x " is a complex number"} (viii) A={x :x " is an isosceles triangle in a planel, B={x:x" is an equilateral triangle in the same plane "} (ix) A={x:x " is a square in a plane "} B={x:x " is a rectangle in the same plane "} (x) A={x:x" is a triangle in a plane "}, B=(x:x " is a rectangle in the same plane"}, (xi) A={x:x " is an even natural number less than " 8} B={x:x " is a natural number which divides" 32}.
Answer» Solution :(iv) `A= {-1, 1} and B ={1} `. So, ` A cancel(sub)B`. (v) `A={2, 4,6,8.....} and B ={ ...., -1, 0,1,2,3,4,5,6,7,8......]`So, ` AsubB`. (vi) Every integer is a RATIONAL number. (VII) We MAY write a real number x as `x ^+0i`. So, every real number is a complex number. (ix) Every square is a RECTANGLE. (xi) `A={2,4,6} and B={1,2,4,8, 16,32}` So, `A cancel(sub) B`.