InterviewSolution
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InterviewSolution
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State Kohlrausch law of independent migration of ions. Write an expression for the molar conductivity of acetic acid at infinite dilution according to Kohlrausch law. `{:((b),"Calculate",:,wedge^(@)m" for acetic acid."),(,"Given that",:,wedge^(@)m(HCl)=426 " S " "cm"^(2)mol^(-1)),(,,,wedge^(@) m(NaCl)=126 " S " cm^(2) mol^(-1)),(,,,wedge^(@) m(CH_(3)COONa)=91 " S " cm^(2)mol^(-1)):}` |
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Answer» (a) Kohlrausch law : It states that limiting molar conductivity of an eletrolyte can be reprsented as the individual contribution of the anion and cation of the electrolyte. `wedge^(@)m(CH_(3)COOH) =lambda_(H^(+))^(@)lambda_(CH_(3)COO^(-))^(@)` (b) `^_(m)^(@)(HCl)" "=lamda_(H^(+))^(@)+lamda_(Cl^(-))^(@)` `wedge^(@)._(m)(NACl)" "=lambda^(@)._(Na^(+)+ lambda^(@)._(Cl)-` `wedge^(@)._(m-)(CH_(3)COONa)" "= lambda^(@)CH_(3)COO^(-^(+))lambda^(@)._(Na^(+))` `wedge^(@)._(m)(CH_(3)COONa)" "lambda^(@)._(H^(+))+lambda^(@)._(Cl^-)+^(@)._(CH_(3)COO^(-))+lambda^(@)._(Na^(+))- lambda^(@)._(Cl^-)-lambda^(@)._(Na`^(+))` `" "=wedge^(@)._(m)(HCl)+wedge^(@)._(m)(CH_(3)COONa)- wedge^(@)._(m) Nacl` `" "=426+91-126` `" "=426+91-126`. |
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