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State the formal charge of each atom in N_(2)O |
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Answer» Solution :Here, FC = formal charge `N_(A)`= number of nonbonding electron Number of e,lectron in valence orbital of N = 5 Number of electron in valence orbital of O = 6SO, TOTAL number of electron = 16, So, FC = valence`bar(e) - (N_(A) + " number of BOND " )` Formal charge of `N_(1) = 5 - (4 + 2) =5 - 6 = - 1 ` Formal charge of `N_(2) = 5 - ( 0 + 4) = + 1 ` Formal charge of `O = 6 - (4 + 2 ) = 0 ` Thus, |
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