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Statement-1 : If n(A) = 3, n(B) = 6, then minimum number of elements in A cup B is 6. Statement-2 : A = {x|x in R, |x| lt 2} and B = {x| x in R,|x| ge 2}. If A cup B = C - R, then C = {x| x in R, 2 ge x lt 3}. Statement-3: The range off(x) = 2^((x^(2) - 2)^(3) + 8) is [1, oo) |
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Answer» TFT |
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