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STATEMENT - 1 : If n is even, .^(2n)C_(1)+.^(2n)C_(3)+.^(2n)C_(5)+"….."+.^(2n)C_(n-1) = 2^(2n-1). STATEMENT - 2 : .^(2n)C_(1) + .^(2n)C_(3)+ .^(2n)C_(5)+ "……"+ .^(2n)C_(2n-1) = 2^(2n-1) |
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Answer» STATEMENT - 1 is true, STATEMENT - 2 is true and STATEMENT - 2 is CORRECT explanation for STATEMENT - 1. |
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