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Statement - 1 : If `x gt 1` then `log_(10)x lt log_(3)x lt log_(e )x lt log_(2)x`. Statement - 2 : If `0 lt x lt 1`, then `log_(x)a gt log_(x)b implies a lt b`.A. Statement - 1 is True, Statement - 2 si True , Statement -2 is a correct explanation for Statement - 1B. Statement -1 is True, Statement -2 si True, Statemetn -2 is NOT a correct explanation for Statement -1C. Statement - 1 is True, Statement - 2 is FalseD. Statement - 1 is False, Statement - 2 is True |
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Answer» Correct Answer - B Statement -1 : If `x gt 1` then ………….. Since `10gt 3gt egt2` If `x gt 1, then log, 10 gt log_(x)3 gt log_(x)e gt log_(x)2` `implies (1)/(log_(10)) gt (1)/(log_(3)x)gt (1)/(log_(e )x)gt (1)/(log_(2)x)` `implies log_(10)x lt log_(3)x lt log_(e )x lt log_(2)x` |
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