Statement I: Aniline on reaction with ` NaNO_2HCl` at `0^@C` followed by coupling with `beta`-naphthol gives a dark blue coloured precipitate. Statement II: The colour of the compound formed in the reaction of aniline with `NaNO_2//HCl` at ` 0^@C` followed by coupling with `beta`-naphthol is due to extended conjugation.A. Statement-I is True, Statement-II is True : Statement-II is a correct explanation for Statement-IB. Statement-I is True, Statement-II is True : Statement-II is `NOT` a correct explanation for Statement-IC. Statement-I is True, Statement-II is False.D. Statement-I is False, Statement-II is True.

Statement I: Aniline on reaction with ` NaNO_2HCl` at `0^@C` followed

1.	Statement I: Aniline on reaction with ` NaNO_2HCl` at `0^@C` followed by coupling with `beta`-naphthol gives a dark blue coloured precipitate. Statement II: The colour of the compound formed in the reaction of aniline with `NaNO_2//HCl` at ` 0^@C` followed by coupling with `beta`-naphthol is due to extended conjugation.A. Statement-I is True, Statement-II is True : Statement-II is a correct explanation for Statement-IB. Statement-I is True, Statement-II is True : Statement-II is `NOT` a correct explanation for Statement-IC. Statement-I is True, Statement-II is False.D. Statement-I is False, Statement-II is True.
Answer» Correct Answer - D

Discussion

No Comment Found

Related InterviewSolutions

An organic compound `C_(3)H_(6)O` does not give a precipitate with 2,4-Dintirophenyl hydrazine reagent-A. `CH_(3)CH_(2)CHO`B. `CH_(3)COCH_(3)`C. `CH_(2)=CH-CH_(2)OH`D.
Which of the following will give yellow precipitate with `I_(2)//NaOH`-A. `ICH_(2)COCH_(2)CH_(2)`B. `CH_(2)COOCOCH_(3)`C. `CH_(3)CONH_(2)`D. `CH_(3)CH(OH)CH_(2)CH_(3)`
`C_(5)H_(10)` represents three isomeric alkenes `A_(1),A_(2)` and `A_(3)`. Each on hydrogeration gives `2-`methylbutane. `A_(1)` and `A_(2)` on oxymercuration-demercuration give the same `3^(o)` alcohol. `A_(2)` and `A_(3)` on hydroboration oxidation give different `1^(o)` alcohol. Assign structures to `A_(1), A_(2)` and `A_(3)` and explain the reactions.
`2-`Methylbutane on reacting with bromine in the presence of sunlight gives mainlyA. `2-`bremo`-2-`methylbutaneB. `1-`bromo`-2-`methylbutaneC. `1-`bromo`-3-`methylbutaneD. `2-`bromo`-3-`methylbutane
In the reaction `CH_(2)Br+Mgoverset("dry ether")rarrA+CH_(3)CHOrarr"adduct"overset(H_(3)O^(o+))rarrB`. The product (B) is :A. B. C. D.
Acetaldehyde reacts with NaoH to form:-A. `CH_(3)-CH_(2)-overset(OH)overset(|)CH-overset(H)overset(|)C=O`B. `CH_(3)-overset(OH)overset(|)CH-CH_(2)-overset(H)overset(|)C=O`C. `CH_(3)-underset(OH)underset(|)CH-underset(O)underset(||)C-CH_(3)`D. `underset(OH)underset(|)CH_(2)-CH_(2)=CH_(2)-underset(H)underset(|)C=O`
`1-`Methylcyclohexene is allowed to react with `B_(2)H_(6)`. The product is then treated with `H_(2)O_(2)` and `NaOH`. The reaction is - The product formed isA. `1-`methylcyclohexanolB. `2-`methylcyclohexanolC. methylcyclohexaneD. cyclohexanol
Which one of the following reagents is suitable for the converston of 2-cyclohexansion into 3-methylcyclohexanone ?A. `CH_(3)Mgl`B. `(CH_(3))_(2)CuLi`C. `CH_(3)I_(2)` and `Zn`D. `CH_(3)AlCl_(2)`
2-Methylcyclohexanone is allowed to react with metachloroperoxobenzoic acid. The major product formed in the reaction isA. B. C. D.
In the reaction The product (A) is :A. B. C. D.

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment