Statement I : In a standing wave on a string , the spacing between nodes is Delta x. If the tension in string is increased wave same as before , then the separation between nearest node and antinode will be Delta x. Statement II : Spacing between nodes ( consecutive) in the standing wave is equal to half of the wavelength of component waves.

Statement I : In a standing wave on a string , the spacing between nod

1.	Statement I : In a standing wave on a string , the spacing between nodes is Delta x. If the tension in string is increased wave same as before , then the separation between nearest node and antinode will be Delta x. Statement II : Spacing between nodes ( consecutive) in the standing wave is equal to half of the wavelength of component waves.
Answer» STATEMENT I is true , Statement II is true , Statement II is a correct explanation for Statement I. Statement I is true , Statement II is true , Statement II is NOT a correct explanation for Statement I. Statement I is true , Statement II is FALSE. Statement I : is false , Statement II is true. Solution :As tension is increased to `4` times , the wave speed (of component waves) increases by a factor of `2` and hence the WAVELENGTH . The spacing between two CONSECUTIVE nodes in STANDING waves is equal to half of wavelength of component waves before increasing the tension , then `Delta x = lambda//2`. After increasing the tension in string `Deltax'` ( spacing between different nodes) ` = ( 2 lambda)/(2) = 2 Delta x` ltbegt So , spacing between the node and antinode is `(Delta x')/(2) = Delta x`