Statement I: `Me-C-=N` and `Me -Nvec(=)C` are not functional isomers. Statement II: As in HCN cynide and isocyanide groups are iterconvertible into each other and remains equilibrium .A. If both statement-I and statement II are true & the statement II is a correct explanation of the statement IB. If both statemetn -I and Statement II are True and Statement II is not a correct explanation of the Statement IC. If Statement -I is True but the Statement -II is falseD. If Statement -I is false but the Statement -II is True.

Statement I: `Me-C-=N` and `Me -Nvec(=)C` are not functional isomers.

1.	Statement I: `Me-C-=N` and `Me -Nvec(=)C` are not functional isomers. Statement II: As in HCN cynide and isocyanide groups are iterconvertible into each other and remains equilibrium .A. If both statement-I and statement II are true & the statement II is a correct explanation of the statement IB. If both statemetn -I and Statement II are True and Statement II is not a correct explanation of the Statement IC. If Statement -I is True but the Statement -II is falseD. If Statement -I is false but the Statement -II is True.
Answer» Correct Answer - D [`Me-C-=N` and `Me-Nvec(=)C` are functional isomers but `H-C-=N` and `H-Nvec(=)C` are Tautomer]